Homework

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Note: When downloading homework 2, wait until the download is complete. The exercise should end with a diagram of 5 places connected by roads.

Homework 1 | Homework 2 | Homework 3 | Homework 4 | Homework 5

Exercise 1
In order to complete Exercise 1, you must be able to plot straight lines on a graph. Find two points that satisfy the rent equation for each crop and draw a straight line through these points. Do this by choosing a reasonable value for distance and solving the equation for the corresponding value of economic rent. This pair of values represents a point on the graph; it is a set of coordinates. When you solved the equation, you calculated the rent value at the distance you chose. You need two points to draw the rent line for each of the three crops. If you get a negative value for rent when you solve the equation, choose a smaller value for distance. Make sure your two points are far enough apart so that your line can be drawn accurately. Question 2 asks you to use the rent lines you have created to draw a map of the crop zones. I want to make sure that you can translate from the graphed results to the pattern of landuse that will appear on the ground. A simple sketch map will suffice.

Before you attempt to answer questions 3 and 4, make sure you have drawn the three rent lines correctly. Then visualize what the rent lines for crops A and B would have to look like in order for the conditions described in questions 3 and 4 to be true. In other words, in order for crop A to be the only crop grown, what would its rent line look like? Use a set of coordinates from this "new" rent line to figure out what the transportation rate would have to be. Follow a similar procedure to solve question 4.

This solution is for one of the three versions of the homework. If your version is different, subsitute the numbers on your sheet in the appropriate places. The basic nature of the solutions is the same for all three versions.

Exercise 2
To complete Exercise 2, you must calculate the population potential and the transportation potential for five hypothetical cities. Each potential figure is the sum of five terms (numbers). In the case of population potential, each of the five numbers is a fraction made up of the population of each place divided by the distance between the city for which the potential is being calculated and each other city. For the transportation potential, each figure is made up of the product of the population and the distance. For the term that applies to the city itself (that is, the city for which the potential is being calculated), use a distance of 1.00 even though, in reality, the distance between a place and itself is zero. (As you know, you cannot divide by zero.)

A simple case for three cities is given below.

  1. Population of city A = 350
  2. Population of city B = 300; Distance from B to A = 50 miles
  3. Population of city C = 250; Distance from C to A = 35 miles; Distance from C to B = 27 miles

The population potential of A = (pop of B)/(dist A to B) + (pop of C)/(dist A to C) + (pop of A)/1.00 = 300/50 + 250/35 + 350/1 = 363.14

The population potential of B = 350/50 + 250/27 + 300/1 = 316.26

The population potential of C = 350/35 + 300/27 + 250/1 = 271.11

The transportation potential of A = (300)(50) + (250)(35) + (350)(1)= 24,100

In this example, A has the highest population potential. To express the potentials of B and C as a percent of A, simply divide the value of B's potential by A's, that is, 316.26 /363.14 = .87 or 87 percent. To find the value for C, divide C's potential by 363.14.

As in the case of #1, the solution is for one of several very similar versions of this homework. Your version may be slightly different, so be careful when comparing your results to the solution.

Solution to Homework #2

Exercise 3
Remember that the circles surrounding the two raw material sites and the market are only location symbols. Do not begin with the circles when labeling the lines; start with the first partial circle radiating out from each location.

As in the case of #1 and #2, the solution is for one of several very similar versions of this homework. Your version may be slightly different, so be careful when comparing your results to the solution.

Solution to Homework #3

Exercise 4
This exercise requires you to draw a few central place hexagons that you will use to answer several questions. This process can be difficult if you have never done it before. I will show you how to get started in class. If you miss the in-class hints, you will find this exercise much more difficult.

To answer the questions about the distances between places, I suggest that you use your diagram, measure, and convert to miles. Your answers do not have to be exact, but if your diagams are sloppy and inaccurate, it is possible that you will be unable to answer the distance questions correctly. The questions concerning the areas of the markets do not require any measurements. If you understand central place theory, you should be able to answer these questions easily.

To answer the questions about the market area sizes, remember that the "k" number indicates the relative sizes of market areas as one moves up or down the urban hierarchy. In a k=3 system, the market area of a central place is three times the size of the next smallest market area. If, for example, the smallest market area is one square mile, the next largest market area will be three square miles, and the next largest will be nine square miles. If it is a k=4 network, the market areas will be multiples by four.

As in the case of #1, #2, and #3, the solution is for one of several very similar versions of this homework. Your version may be slightly different, so be careful when comparing your results to the solution.

Solution to homework #4 page 1

Exercise 5
When completing the questions for this exercise, try to be accurate, but do not worry about reading the graph exactly. Except in unusual circumstances, graphs are not meant to provide precise numerical data. As long as the numbers you use are close, you will not be penalized. Remember that not all cells in the table should have entries.

Solution to homework #5